-6y^2-19y+20=0

Solution for -6y^2-19y+20=0 equation:

-6y^2-19y+20=0

a = -6; b = -19; c = +20;
Δ = b2-4ac
Δ = -192-4·(-6)·20
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-19)-29}{2*-6}=\frac{-10}{-12}
=5/6
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-19)+29}{2*-6}=\frac{48}{-12}
=-4
$